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Convert [Megaelectron Volt] to [Foot Pound], (MeV to ftlb)

ENERGY


398400 Megaelectron Volt
= 4.7079148559543E-8 Foot Pound
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Category: energy
Conversion: Megaelectron Volt to Foot Pound
The base unit for energy is joules (Non-SI/Derived Unit)
[Megaelectron Volt] symbol/abbrevation: (MeV)
[Foot Pound] symbol/abbrevation: (ftlb)

How to convert Megaelectron Volt to Foot Pound (MeV to ftlb)?
1 MeV = 1.1817055361331E-13 ftlb.
398400 x 1.1817055361331E-13 ftlb = 4.7079148559543E-8 Foot Pound.
Always check the results; rounding errors may occur.

Definition:
In relation to the base unit of [energy] => (joules), 1 Megaelectron Volt (MeV) is equal to 1.60218E-13 joules, while 1 Foot Pound (ftlb) = 1.35582 joules.
398400 Megaelectron Volt to common energy units
398400 MeV = 6.38308512E-8 joules (J)
398400 MeV = 6.38308512E-11 kilojoules (kJ)
398400 MeV = 1.525593957935E-8 calories (cal)
398400 MeV = 1.525593957935E-11 kilocalories (kcal)
398400 MeV = 398400000000 electron volt (eV)
398400 MeV = 1.7730792E-11 watt hour (Wh)
398400 MeV = 14640963139.12 atomic unit of energy (au)
398400 MeV = 1.525593957935E-17 tons of TNT (tTNT)
398400 MeV = 4.7079219801269E-8 foot pound force (ft lbf)
398400 MeV = 0.638308512 ergs (ergs)
(Megaelectron Volt) to (Foot Pound) conversions

Megaelectron Volt to random (energy units)

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