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Convert [Foot Pound Force] to [Atomic Bomb [nuclear Weapon]], (ft lbf to at bomb)

ENERGY


717000 Foot Pound Force
= 1.215151836192E-8 Atomic Bomb [nuclear Weapon]
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Category: energy
Conversion: Foot Pound Force to Atomic Bomb [nuclear Weapon]
The base unit for energy is joules (Non-SI/Derived Unit)
[Foot Pound Force] symbol/abbrevation: (ft lbf)
[Atomic Bomb [nuclear Weapon]] symbol/abbrevation: (at bomb)

How to convert Foot Pound Force to Atomic Bomb [nuclear Weapon] (ft lbf to at bomb)?
1 ft lbf = 1.6947724354143E-14 at bomb.
717000 x 1.6947724354143E-14 at bomb = 1.215151836192E-8 Atomic Bomb [nuclear Weapon].
Always check the results; rounding errors may occur.

Definition:

Atomic Bombs or Nuclear weapons have a large variety of energy yields. The first detonated on July 16, 1945 near Alamogordo, New Mexico, had a yield of a ..more definition+

In relation to the base unit of [energy] => (joules), 1 Foot Pound Force (ft lbf) is equal to 1.3558179483314 joules, while 1 Atomic Bomb [nuclear Weapon] (at bomb) = 80000000000000 joules.
717000 Foot Pound Force to common energy units
717000 ft lbf = 972121.46895361 joules (J)
717000 ft lbf = 972.12146895361 kilojoules (kJ)
717000 ft lbf = 232342.60730249 calories (cal)
717000 ft lbf = 232.34260730249 kilocalories (kcal)
717000 ft lbf = 6.0674922228065E+24 electron volt (eV)
717000 ft lbf = 270.033741376 watt hour (Wh)
717000 ft lbf = 2.2297673188004E+23 atomic unit of energy (au)
717000 ft lbf = 0.00023234260730249 tons of TNT (tTNT)
717000 ft lbf = 717000 foot pound force (ft lbf)
717000 ft lbf = 9721214689536.1 ergs (ergs)
(Foot Pound Force) to (Atomic Bomb [nuclear Weapon]) conversions

Foot Pound Force to random (energy units)

Random [energy unit] conversions