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Convert [Megaelectron Volt] to [Foot Pound], (MeV to ftlb)

ENERGY


231000 Megaelectron Volt
= 2.7297397884675E-8 Foot Pound
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Category: energy
Conversion: Megaelectron Volt to Foot Pound
The base unit for energy is joules (Non-SI/Derived Unit)
[Megaelectron Volt] symbol/abbrevation: (MeV)
[Foot Pound] symbol/abbrevation: (ftlb)

How to convert Megaelectron Volt to Foot Pound (MeV to ftlb)?
1 MeV = 1.1817055361331E-13 ftlb.
231000 x 1.1817055361331E-13 ftlb = 2.7297397884675E-8 Foot Pound.
Always check the results; rounding errors may occur.

Definition:
In relation to the base unit of [energy] => (joules), 1 Megaelectron Volt (MeV) is equal to 1.60218E-13 joules, while 1 Foot Pound (ftlb) = 1.35582 joules.
231000 Megaelectron Volt to common energy units
231000 MeV = 3.7010358E-8 joules (J)
231000 MeV = 3.7010358E-11 kilojoules (kJ)
231000 MeV = 8.8456878585086E-9 calories (cal)
231000 MeV = 8.8456878585086E-12 kilocalories (kcal)
231000 MeV = 231000000000 electron volt (eV)
231000 MeV = 1.0280655E-11 watt hour (Wh)
231000 MeV = 8489112663.4958 atomic unit of energy (au)
231000 MeV = 8.8456878585086E-18 tons of TNT (tTNT)
231000 MeV = 2.7297439192001E-8 foot pound force (ft lbf)
231000 MeV = 0.37010358 ergs (ergs)
(Megaelectron Volt) to (Foot Pound) conversions

Megaelectron Volt to random (energy units)

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