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Convert [Millielectron Volt] to [Calories 20°C], (meV to cal20°C)

ENERGY


711200 Millielectron Volt
= 2.7247672493364E-17 Calories 20°C
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Category: energy
Conversion: Millielectron Volt to Calories 20°C
The base unit for energy is joules (Non-SI/Derived Unit)
[Millielectron Volt] symbol/abbrevation: (meV)
[Calories 20°C] symbol/abbrevation: (cal20°C)

How to convert Millielectron Volt to Calories 20°C (meV to cal20°C)?
1 meV = 3.8312250412492E-23 cal20°C.
711200 x 3.8312250412492E-23 cal20°C = 2.7247672493364E-17 Calories 20°C.
Always check the results; rounding errors may occur.

Definition:
In relation to the base unit of [energy] => (joules), 1 Millielectron Volt (meV) is equal to 1.60218E-22 joules, while 1 Calories 20°C (cal20°C) = 4.1819 joules.
711200 Millielectron Volt to common energy units
711200 meV = 1.139470416E-16 joules (J)
711200 meV = 1.139470416E-19 kilojoules (kJ)
711200 meV = 2.7233996558317E-17 calories (cal)
711200 meV = 2.7233996558317E-20 kilocalories (kcal)
711200 meV = 711.2 electron volt (eV)
711200 meV = 3.1651956E-20 watt hour (Wh)
711200 meV = 26.136177170036 atomic unit of energy (au)
711200 meV = 2.7233996558317E-26 tons of TNT (tTNT)
711200 meV = 8.4043024906282E-17 foot pound force (ft lbf)
711200 meV = 1.139470416E-9 ergs (ergs)
(Millielectron Volt) to (Calories 20°C) conversions

Millielectron Volt to random (energy units)

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