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Convert [Gigaelectron Volt] to [Foot Poundal], (GeV to ft pdl)

ENERGY


4950 Gigaelectron Volt
= 1.8820052872066E-9 Foot Poundal
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Category: energy
Conversion: Gigaelectron Volt to Foot Poundal
The base unit for energy is joules (Non-SI/Derived Unit)
[Gigaelectron Volt] symbol/abbrevation: (GeV)
[Foot Poundal] symbol/abbrevation: (ft pdl)

How to convert Gigaelectron Volt to Foot Poundal (GeV to ft pdl)?
1 GeV = 3.8020308832457E-13 ft pdl.
4950 x 3.8020308832457E-13 ft pdl = 1.8820052872066E-9 Foot Poundal.
Always check the results; rounding errors may occur.

Definition:
In relation to the base unit of [energy] => (joules), 1 Gigaelectron Volt (GeV) is equal to 1.60218E-10 joules, while 1 Foot Poundal (ft pdl) = 421.401100938 joules.
4950 Gigaelectron Volt to common energy units
4950 GeV = 7.930791E-7 joules (J)
4950 GeV = 7.930791E-10 kilojoules (kJ)
4950 GeV = 1.895504541109E-7 calories (cal)
4950 GeV = 1.895504541109E-10 kilocalories (kcal)
4950 GeV = 4950000000000 electron volt (eV)
4950 GeV = 2.2029975E-10 watt hour (Wh)
4950 GeV = 181909557074.91 atomic unit of energy (au)
4950 GeV = 1.895504541109E-16 tons of TNT (tTNT)
4950 GeV = 5.8494512554288E-7 foot pound force (ft lbf)
4950 GeV = 7.930791 ergs (ergs)
(Gigaelectron Volt) to (Foot Poundal) conversions

Gigaelectron Volt to random (energy units)

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